3.29 \(\int \frac {1}{x^2 (a+b \text {csch}(c+d x^2))^2} \, dx\)

Optimal. Leaf size=21 \[ \text {Int}\left (\frac {1}{x^2 \left (a+b \text {csch}\left (c+d x^2\right )\right )^2},x\right ) \]

[Out]

Unintegrable(1/x^2/(a+b*csch(d*x^2+c))^2,x)

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Rubi [A]  time = 0.03, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{x^2 \left (a+b \text {csch}\left (c+d x^2\right )\right )^2} \, dx \]

Verification is Not applicable to the result.

[In]

Int[1/(x^2*(a + b*Csch[c + d*x^2])^2),x]

[Out]

Defer[Int][1/(x^2*(a + b*Csch[c + d*x^2])^2), x]

Rubi steps

\begin {align*} \int \frac {1}{x^2 \left (a+b \text {csch}\left (c+d x^2\right )\right )^2} \, dx &=\int \frac {1}{x^2 \left (a+b \text {csch}\left (c+d x^2\right )\right )^2} \, dx\\ \end {align*}

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Mathematica [F]  time = 180.00, size = 0, normalized size = 0.00 \[ \text {\$Aborted} \]

Verification is Not applicable to the result.

[In]

Integrate[1/(x^2*(a + b*Csch[c + d*x^2])^2),x]

[Out]

$Aborted

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fricas [A]  time = 0.41, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {1}{b^{2} x^{2} \operatorname {csch}\left (d x^{2} + c\right )^{2} + 2 \, a b x^{2} \operatorname {csch}\left (d x^{2} + c\right ) + a^{2} x^{2}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^2/(a+b*csch(d*x^2+c))^2,x, algorithm="fricas")

[Out]

integral(1/(b^2*x^2*csch(d*x^2 + c)^2 + 2*a*b*x^2*csch(d*x^2 + c) + a^2*x^2), x)

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giac [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{{\left (b \operatorname {csch}\left (d x^{2} + c\right ) + a\right )}^{2} x^{2}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^2/(a+b*csch(d*x^2+c))^2,x, algorithm="giac")

[Out]

integrate(1/((b*csch(d*x^2 + c) + a)^2*x^2), x)

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maple [A]  time = 0.57, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^{2} \left (a +b \,\mathrm {csch}\left (d \,x^{2}+c \right )\right )^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^2/(a+b*csch(d*x^2+c))^2,x)

[Out]

int(1/x^2/(a+b*csch(d*x^2+c))^2,x)

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maxima [A]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {{\left (a^{3} d e^{\left (2 \, c\right )} + a b^{2} d e^{\left (2 \, c\right )}\right )} x^{2} e^{\left (2 \, d x^{2}\right )} + a b^{2} - {\left (a^{3} d + a b^{2} d\right )} x^{2} - {\left (b^{3} e^{c} - 2 \, {\left (a^{2} b d e^{c} + b^{3} d e^{c}\right )} x^{2}\right )} e^{\left (d x^{2}\right )}}{{\left (a^{5} d e^{\left (2 \, c\right )} + a^{3} b^{2} d e^{\left (2 \, c\right )}\right )} x^{3} e^{\left (2 \, d x^{2}\right )} + 2 \, {\left (a^{4} b d e^{c} + a^{2} b^{3} d e^{c}\right )} x^{3} e^{\left (d x^{2}\right )} - {\left (a^{5} d + a^{3} b^{2} d\right )} x^{3}} - \int \frac {3 \, a b^{2} - {\left (3 \, b^{3} e^{c} - 2 \, {\left (2 \, a^{2} b d e^{c} + b^{3} d e^{c}\right )} x^{2}\right )} e^{\left (d x^{2}\right )}}{{\left (a^{5} d e^{\left (2 \, c\right )} + a^{3} b^{2} d e^{\left (2 \, c\right )}\right )} x^{4} e^{\left (2 \, d x^{2}\right )} + 2 \, {\left (a^{4} b d e^{c} + a^{2} b^{3} d e^{c}\right )} x^{4} e^{\left (d x^{2}\right )} - {\left (a^{5} d + a^{3} b^{2} d\right )} x^{4}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^2/(a+b*csch(d*x^2+c))^2,x, algorithm="maxima")

[Out]

-((a^3*d*e^(2*c) + a*b^2*d*e^(2*c))*x^2*e^(2*d*x^2) + a*b^2 - (a^3*d + a*b^2*d)*x^2 - (b^3*e^c - 2*(a^2*b*d*e^
c + b^3*d*e^c)*x^2)*e^(d*x^2))/((a^5*d*e^(2*c) + a^3*b^2*d*e^(2*c))*x^3*e^(2*d*x^2) + 2*(a^4*b*d*e^c + a^2*b^3
*d*e^c)*x^3*e^(d*x^2) - (a^5*d + a^3*b^2*d)*x^3) - integrate((3*a*b^2 - (3*b^3*e^c - 2*(2*a^2*b*d*e^c + b^3*d*
e^c)*x^2)*e^(d*x^2))/((a^5*d*e^(2*c) + a^3*b^2*d*e^(2*c))*x^4*e^(2*d*x^2) + 2*(a^4*b*d*e^c + a^2*b^3*d*e^c)*x^
4*e^(d*x^2) - (a^5*d + a^3*b^2*d)*x^4), x)

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mupad [A]  time = 0.00, size = -1, normalized size = -0.05 \[ \int \frac {1}{x^2\,{\left (a+\frac {b}{\mathrm {sinh}\left (d\,x^2+c\right )}\right )}^2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^2*(a + b/sinh(c + d*x^2))^2),x)

[Out]

int(1/(x^2*(a + b/sinh(c + d*x^2))^2), x)

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sympy [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^{2} \left (a + b \operatorname {csch}{\left (c + d x^{2} \right )}\right )^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**2/(a+b*csch(d*x**2+c))**2,x)

[Out]

Integral(1/(x**2*(a + b*csch(c + d*x**2))**2), x)

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